1+1/12=-6t^2+13t+5

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Solution for 1+1/12=-6t^2+13t+5 equation: 


t in (-oo:+oo)

1/12+1 = 13*t-6*t^2+5 // - 13*t-6*t^2+5

1/12-(-6*t^2)-(13*t)-5+1 = 0

6*t^2-13*t+1/12-5+1 = 0

6*t^2-13*t-47/12 = 0

DELTA = (-13)^2-(-47/12*4*6)

DELTA = 263

DELTA > 0

t = (263^(1/2)+13)/(2*6) or t = (13-263^(1/2))/(2*6)

t = (263^(1/2)+13)/12 or t = (13-263^(1/2))/12

t in { (13-263^(1/2))/12, (263^(1/2)+13)/12 }

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